Riddle/Puzzle Thread

[Smitty]

Thanks to DarkMerlin from ChattyBastidges for this game

This is similiar to mindtrap where there are riddles on the cards..Try to figure them out and if you get it right post one of your own.

I'll start off with an easy one, and once someone answers it correctly that person then comes up with another riddle and it continues.

First Riddle:

#1: A new medical building containing 100 offices has just been completed. A painter was hired to paint the numbers 1 to 100 on the doors. How many times will he have to paint the number nine?

 

[Janseagle]

10, ha im wrong

 

[Bjornita]

20.

 

[Smitty]

|B|j|o|r|n|i|t|a| is right the answer is 20 now come up with another one =)

 

[Bjornita]

okay, a good old-fashioned easy train question.

two trains start out from the same station, the second train leaving two hours after the first. the first train is travelling at 50 mph and the second is travelling at 60 mph. after how many hours will the second train overtake the first?

 

[flashflores2]

* thinking...E=Mc2#C©¤{OO*+o"A¨^47f3 .... still thinking* AH!!! I have got it! The second train will overtake the 2nd train after a couple of hours.

 

[Bjornita]

good answer, but a bit more prescise......

 

[Bjornita]

actually, i made this up spur-of-the-moment because we finished that in math, and this is a fairly easy one

 

[Smitty]

2 Hours?

 

[Bjornita]

no no no. i'll just post the answer. the answer is 10 hours. here's how you get it:

let x equal the time for train 2.

rt=d (d=rt) --->train 1: r: 50 t: x+2 d: 50(x+2)
rt=d (d=rt) --->train 2: r: 60 t: x d: 60x

they have to be equal, because that's what you're finding out.....so

50(x+2) = 60x <------distribute the 50
50x + 100 = 60x <-----get all of the x's on one side, the numbers on the other (subtract 50x from both sides)
100 = 10x <------divide by 10 on both sides to get x by itself
10 = x

so it would take 10 hours for train 2 to catch up with train 1.

 

[Bjornita]

who would make up the next question, then?

 

[Tacitus]

just make another one that doesn't include math, between you and me, no one else here could have probably figured that out(maybe jans), but on weekends, my brain is in shut down, so i don't do math

 

[flashflores2]

Originally posted by |B|j|o|r|n|i|t|a|
no no no. i'll just post the answer. the answer is 10 hours. here's how you get it:

let x equal the time for train 2.

rt=d (d=rt) --->train 1: r: 50 t: x+2 d: 50(x+2)
rt=d (d=rt) --->train 2: r: 60 t: x d: 60x

they have to be equal, because that's what you're finding out.....so

50(x+2) = 60x <------distribute the 50
50x + 100 = 60x <-----get all of the x's on one side, the numbers on the other (subtract 50x from both sides)
100 = 10x <------divide by 10 on both sides to get x by itself
10 = x

so it would take 10 hours for train 2 to catch up with train 1.

um.......i dont get how you got 50(x+2) = 60x. I can solve it from there..(distributive property) but i got nothing b4 that. Is it rate x time = distance?

 

[Bjornita]

yea. that's the formula for distance.

 

[flashflores2]

Oh. Ok cool, I am right for once.

 

[Comin2TakeUAway]

its not that hard, just roll up your sleves and get dirty.

 

[landar]

what is the qestion

 

[Comin2TakeUAway]

just talking about the last question that was asked